2m^2-3m=20

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Solution for 2m^2-3m=20 equation:


Simplifying
2m2 + -3m = 20

Reorder the terms:
-3m + 2m2 = 20

Solving
-3m + 2m2 = 20

Solving for variable 'm'.

Reorder the terms:
-20 + -3m + 2m2 = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + -3m + 2m2 = 0

Factor a trinomial.
(-5 + -2m)(4 + -1m) = 0

Subproblem 1

Set the factor '(-5 + -2m)' equal to zero and attempt to solve: Simplifying -5 + -2m = 0 Solving -5 + -2m = 0 Move all terms containing m to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -2m = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -2m = 0 + 5 -2m = 0 + 5 Combine like terms: 0 + 5 = 5 -2m = 5 Divide each side by '-2'. m = -2.5 Simplifying m = -2.5

Subproblem 2

Set the factor '(4 + -1m)' equal to zero and attempt to solve: Simplifying 4 + -1m = 0 Solving 4 + -1m = 0 Move all terms containing m to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1m = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1m = 0 + -4 -1m = 0 + -4 Combine like terms: 0 + -4 = -4 -1m = -4 Divide each side by '-1'. m = 4 Simplifying m = 4

Solution

m = {-2.5, 4}

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